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How many moles of Pb(NO3)2 are required if 8 moles of PbCI2 are produced?
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transitionstate: PbCl₂ can be synthesized from Pb(NO₃)₂ using various reagents. I will be using HCl as follow,
Pb(NO₃)₂ + 2 HCl → PbCl₂ + 2 HNO₃
According to equation,
1 mole of PbCl₂ is formed by = 1 mole of Pb(NO₃)₂
So,
8 moles of PbCl₂ will be produced by = X moles of Pb(NO₃)₂
Solving for X,
X = (8 mol × 1 mol) ÷ 1 mol
X = 8 mol of Pb(NO₃)₂
Result:
8 mol of Pb(NO₃)₂ are required to produce 8 moles of PbCl₂.
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