can someone please explain to me how to do this.

• : y = x² - 4x + 4
  y = 2x - 4
  
  Find intersection of L and C:
  x² - 4x + 4 = 2x - 4
  x² - 6x + 8 = 0
  (x - 2)(x - 4) = 0
  x = 2 or x = 4
  
  When x = 2 , y = 2(2) - 4 = 0
  When x = 4, y = 2(4) - 4 = 4
  
  Points of intersection = A(2, 0) and B(4, 4)
  
  Find the length of AB:
  
  [tex] \text {Length of AB}= \sqrt{(4-0)^2 + (4-2)^2} = \sqrt{16 + 4} = \sqrt{20} = 4.47 \text{ units}[/tex]
  
  Answer: 4.47 units